selveral priority to choose which char to represent corresponding english number:

  1. unique among all english numbers.

  2. less freqency in other words if not unique Also, note ```python class Solution: def originalDigits(self, s: str) -> str: “”” zero z one o 1-0-2-4 two w three h 3-8 four u five v 5-7 six x seven s 7-6 eight g nine i 9-8-6-5

     """
 # step1 create a array as map index as key, value as freq 
 cnt = [0] * 10
 # step2 count each unique char's freq 
 counter = collections.Counter(s)
 # step3 first even then odd 
 cnt[0] = counter['z'] 
 cnt[2] = counter['w']
 cnt[4] = counter['u']
 cnt[6] = counter['x']
 cnt[8] = counter['g']
 # step4 process odd numbser
 cnt[3] = counter['h'] - cnt[8]
 cnt[7] = counter['s'] - cnt[6]
 cnt[5] = counter['v'] - cnt[7]
 cnt[1] = counter['o'] - cnt[0] - cnt[2] -cnt[4]
 cnt[9] = counter['i'] - cnt[5] - cnt[6] -cnt[8]
 # step5, join string together
    
 res = []
 for num in range(len(cnt)):
     if cnt[num] != 0:
         res.append(str(num)* cnt[num])
 return ''.join(res)

```